列表推导是Python中一种流行的技术。在这里,我们使用这种技术。我们创建了一个用户输入数组,并且数组元素应以随机顺序为0和1。然后将左侧的0和右侧的1分开。我们遍历数组并分离两个不同的列表,一个包含0,另一个包含1,然后连接两个列表。
Input:: a=[0,1,1,0,0,1] Output::[0,0,0,1,1,1]
seg0s1s(A) /* A is the user input Array and the element of A should be the combination of 0’s and 1’s */ Step 1: First traverse the array. Step 2: Then check every element of the Array. If the element is 0, then its position is left side and if 1 then it is on the right side of the array. Step 3: Then concatenate two list.
# Segregate 0's and 1's in an array list
def seg0s1s(A):
n = ([i for i in A if i==0] + [i for i in A if i==1])
print(n)
# Driver program
if __name__ == "__main__":
A=list()
n=int(input("Enter the size of the array ::"))
print("Enter the number ::")
for i in range(int(n)):
k=int(input(""))
A.append(int(k))
print("The New ArrayList ::")
seg0s1s(A)输出结果
Enter the size of the array ::6 Enter the number :: 1 0 0 1 1 0 The New ArrayList :: [0, 0, 0, 1, 1, 1]