当弹出窗口即将可见时，将触发show.bs.popover事件。
触发弹出事件-
$("[data-toggle='popover']").on('show.bs.popover', function(){
alert('Popover is about to be visible!');
});您可以尝试运行以下代码来实现show.bs.popover事件-
<!DOCTYPE html>
<html lang="en">
<head>
<title>Bootstrap Example</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://cdn.staticfile.org/jquery/3.3.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</head>
<body>
<div class="container">
<a href="#" data-toggle="popover" title="Employee ID" data-content="E001, E004, E008">Awards</a>
<div>
<p>Here's the list:</p>
<button type="button" class="btn btn-default">List</button>
</div>
</div>
<script>
$(document).ready(function(){
$(".btn-default").click(function(){
$("[data-toggle='popover']").popover('show');
});
$("[data-toggle='popover']").on('show.bs.popover', function(){
alert('Popover is about to be visible!');
});
});
</script>
</body>
</html>