在本节中，我们将看到如何生成所有可能的任何长度的字符串，这将使用每种字符组合来构成字符串。例如，如果字符串是ABC，则它将生成-{A，B，C，AB，BA，BC，CB，CA，AC，ABC，ACB，BAC，BCA，CAB，CBA}
让我们看一个例子来了解这个想法。
Begin n := length of the string str count is 2^n – 1 for each number 0 to count, do sub_str := empty string for j in range 0 to n, do if jth bit of the counter is set, then concatenate jth character of str with sub_str end if done repeat: print sub_string until next permutation of sub_string is not completed done End
#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
void printAllString(string str) {
int n = str.size();
unsigned int count = pow(2, n);
for (int counter = 1; counter <count; counter++) { //generate 2^n - 1 strings
string subs = "";
for (int j = 0; j < n; j++) {
if (counter & (1<<j)) //when the jth bit is set, then add jth character
subs.push_back(str[j]);
}
do{
cout << subs << endl;
}
while (next_permutation(subs.begin(), subs.end()));
}
}输出结果
A B AB BA C AC CA BC CB ABC ACB BAC BCA CAB CBA D AD DA BD DB ABD ADB BAD BDA DAB DBA CD DC ACD ADC CAD CDA DAC DCA BCD BDC CBD CDB DBC DCB ABCD ABDC ACBD ACDB ADBC ADCB BACD BADC BCAD BCDA BDAC BDCA CABD CADB CBAD CBDA CDAB CDBA DABC DACB DBAC DBCA DCAB DCBA