假设以下是带有元素的列表-
ArrayList < String > arrList = new ArrayList < String > ();
arrList.add("Jack");
arrList.add("Tom");
arrList.add("Brad");
arrList.add("Amy");
arrList.add("Ben");
arrList.add("Peter");
arrList.add("Katie");
arrList.add("Tim");现在,使用listIterator()。该next()方法返回列表中的下一个元素。悬停,使用remove()方法删除元素-
ListIterator<String>iterator = arrList.listIterator(); iterator.next(); iterator.remove();
import java.util.ArrayList;
import java.util.ListIterator;
public class Demo {
public static void main(String[] args) {
ArrayList<String>arrList = new ArrayList<String>();
arrList.add("Jack");
arrList.add("Tom");
arrList.add("Brad");
arrList.add("Amy");
arrList.add("Ben");
arrList.add("Peter");
arrList.add("Katie");
arrList.add("Tim");
System.out.println("List...");
for (String str: arrList) {
System.out.println(str);
}
ListIterator<String>iterator = arrList.listIterator();
iterator.next();
iterator.remove();
System.out.println("Updated List...");
for (String str: arrList) {
System.out.println(str);
}
}
}输出结果
List... Jack Tom Brad Amy Ben Peter Katie Tim Updated List... Tom Brad Amy Ben Peter Katie Tim