假设我们有一个对象数组,描述了一些像这样的航班的路线-
const routes = [
{
flyFrom: "CDG",
flyTo: "DUB",
return: 0,
},
{
flyFrom: "DUB",
flyTo: "SXF",
return: 0,
},
{
flyFrom: "SFX",
flyTo: "CDG",
return: 1,
}
];我们需要计算返回的次数-0和返回的次数:1。
最终输出应类似于-
for the cases where return: 0 appears 2 times --- 1 Stop for the cases where return: 1 appears 1 time --- Non-stop
为此的代码将是-
const routes = [
{
flyFrom: "CDG",
flyTo: "DUB",
return: 0,
},
{
flyFrom: "DUB",
flyTo: "SXF",
return: 0,
},
{
flyFrom: "SFX",
flyTo: "CDG",
return: 1,
}
];
const displaySimilar = arr => {
const count = {};
arr.forEach(el => {
count[el.return] = (count[el.return] || 0) + 1;
});
Object.keys(count).forEach(key => {
for(let i = 0; i < count[key]; i++){
if(key === '0'){
console.log('1 Stop');
}
else if(key === '1'){
console.log('Non-stop');
};
}
})
};
displaySimilar(routes);输出结果
控制台中的输出将是-
1 Stop 1 Stop Non-stop